the moment of inertia of composite rod about an axis perpendicular to its length and passing through its centre is?
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Answer:
i think this will be the answer,
moment of inertia of rod=ml^2/12
for rod 1=m1 l1^2 /12
for rod2 =m2 l2^2/12
hence by adding,
moment of inertia=(m1+m2) (l1^2/12+l2^2/12)
i.e,option(2)
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0
Answer:4
Explanation:
Two separate rods can be considered one with mass m1 and length l1 and the other m2, l2
Moment of inertia of rod about axis passing through its end is (ml^2)/3
Therefore
Ans is 4
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