The moment of inertia of disc about its diameter is 2 units. Its moment of inertia about an axis through a point on its rim and in the plane of the disc is.
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⛦Hᴇʀᴇ Is Yoᴜʀ Aɴsᴡᴇʀ⚑
▬▬▬▬▬▬▬▬▬▬▬▬☟
▶Let ‘r’ be the radius of the disc.
♦ Given,
➧ moment of inertia of the disc about PQ, IPQ
➾ 2 units
➧ Moment of inertia of the disc about AB, IAB
➾ ½ Mr²
➧ We need the MI of the disc about RS or IRS.
♦ Now
➧ From theorem of perpendicular axes,
IAB = 2IPQ
➾ ½ Mr² = 2
➾ Mr² = 4
➧ Now, by theorem of parallel axes
IRS
➾ IPQ + Mr²
➾ 2 + 4
➾ 6 units ...✔
_________
Thanks...✊
▬▬▬▬▬▬▬▬▬▬▬▬☟
▶Let ‘r’ be the radius of the disc.
♦ Given,
➧ moment of inertia of the disc about PQ, IPQ
➾ 2 units
➧ Moment of inertia of the disc about AB, IAB
➾ ½ Mr²
➧ We need the MI of the disc about RS or IRS.
♦ Now
➧ From theorem of perpendicular axes,
IAB = 2IPQ
➾ ½ Mr² = 2
➾ Mr² = 4
➧ Now, by theorem of parallel axes
IRS
➾ IPQ + Mr²
➾ 2 + 4
➾ 6 units ...✔
_________
Thanks...✊
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