Question

the moment of inertia of thin rod of mass m and length l about an axis passing through its centre and normal to its length is given by ml^2/12.using theorem of parellel axes.find its moment of inertia about an axis passing through on end andnormal to its length.if l=1m and m=0.2kg

Answer 1

using the parallel axis theorem
I=Ml^2/12 +Ml^2/4
l=Ml^2/3
put m=0.2 l=1
l=1/15