Question

the momentum (in Kg m/s) of photon having 6 MeV energy will be

Answer 1

Answer:

Explanation:

E=h/p where E-energy; h=planck's const; p=momentum

p=h/E i.e. 6.6x10^-34 / 6 x 10^6 x 1.6x10^-19

p=0.68 x 10^-25

Answer 2

Given:

Energy,

E = 6 MeV

To Find:

Momentum,

p = ?

Solution:

As we know,

⇒  $E=\frac{h}{p}$

then

⇒  $p=\frac{h}{E}$

Where,

p = Momentum

h = Planck's const

Now,

On putting the values in the above given formula, we get

⇒  $p=\frac{6.6\times 10^{-34} }{6\times 10^6\times 1.6\times 10^{-19}}$

⇒     $=0.68\times 10^{-25}$

So that the momentum will be "0.68 × 10⁻²⁵".