Chemistry, asked by aftababkhan3231, 9 months ago

The momentum in kgm/s of a photon having 6MeV energy is

Answers

Answered by bhaskarreddymummadi1
1

Answer:

ACC to relation P=E/C E=6Mev=6x10^6x1.6x10^-19

Explanation:P=6x10^6x1.6x10^-19/3x10^8

                        =3.2x10^-21kgm/s

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