The momentum of a body decreases by 2%: and mass of particle decrease by 1% then percentage decrease in its kinetic energy is:
(A) 2% (B) 3% (C) 5% (D) 1%
Answers
Answered by
0
Answer:
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Explanation:
The relation between kinetic energy and momentum is
KE=
2m
p
2
When momentum is increases by 20%, new momentum is p
′
p
′
=p+0.2p
p
′
=1.2p
New kinetic energy
KE
′
=
2m
p
′
2
KE
′
=
2m
(1.2p)
2
KE
′
=
2m
1.44p
2
KE
′
=1.44KE ( from equation 1 )
Change in kinetic energy
ΔKE=
KE
KE
′
−KE
×100
ΔKE=
KE
1.44KE−KE
×100
ΔKE=44%
So, kinetic energy is increased by 44 %
Answered by
0
Explanation:
kinetic energy = p²/2m
ke = p²/m
= (-2)² - 1
= 4 -1 = 3%
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