Question

The momentum of a body increased by 20%.calculate the percentage in the kinetic energy?

Answer 1

⭐⭐⭐ Hey mate!!⭐⭐⭐

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⚡⚡Let k be the kinetic energy

And p be the momentum

Where,

K=1/2mv^2= p^2/2m

Also,

P=mv

Here,

♐M= mass

⚡And v = velocity

Now,

⚡If momentum increas by 20%

Then,

⚡k.E = (P+20P/100)^2/2m

⚡K.E =. P^2( 1.2)^2 /2m

=1.44k.E

Now,

⚡∆k.E = 1.44k.E - K.E

⚡∆K.E = 0.44

Now,

⚡⚡∆k.E / k.E ×100 = 44%

Hence,

⚡Change in k.E = 44%

Hope it will help....✌️✌️

#phoenix⭐