the momentum of a body increases from 150 kg metre per second to 60 kg metre per second in 2 minutes calculate the applied force on a body
Answers
Answered by
3
the momentum of a body decreases from 150 kg.m/s to 60 kg.m/s in 2 minutes
Initial momentum= 150 kg.m/s
final momentum= 60 kg.m/s
time taken = 2 min = 120 second
we know that force = rate of change of momentum
=> F = (final momentum - initial momentum)/time
=> F = (60 - 150)/120
=> F = -90/120
=> F = -0.75 N
Applied force is -0.75 N (Negative sign indicates force was applied in the opposite direction of motion of the body.)
Initial momentum= 150 kg.m/s
final momentum= 60 kg.m/s
time taken = 2 min = 120 second
we know that force = rate of change of momentum
=> F = (final momentum - initial momentum)/time
=> F = (60 - 150)/120
=> F = -90/120
=> F = -0.75 N
Applied force is -0.75 N (Negative sign indicates force was applied in the opposite direction of motion of the body.)
Answered by
2
the momentum of a body decreases from 150 kg.m/s to 60 kg.m/s in 2 minutes
Initial momentum= 150 kg.m/s
final momentum= 60 kg.m/s
time taken = 2 min = 120 second
we know that force = rate of change of momentum
=> F = (final momentum - initial momentum)/time
=> F = (60 - 150)/120
=> F = -90/120
=> F = -0.75 N
Applied force is -0.75 N (Negative sign indicates force was applied in the opposite direction of motion of the body.)
Similar questions