Question

The momentum of a body of mass 15 kg is 50 kg m/s. Find its kinetic energy.​

Answer 1

Explanation:

Solution:-

\longmapsto \sf \: KE = \dfrac{(50 \: kgm {s}^{ - 1} )^2}{2(15 \: kg)}⟼KE=

2(15kg)

(50kgms

−1

)

2

⠀

\longmapsto \sf \:KE = \dfrac{50 \: kgm {s}^{ - 1} \times 50 \: kgm {s}^{ - 1} }{30 \: kg}⟼KE=

30kg

50kgms

−1

×50kgms

−1

⠀

\longmapsto \sf \: KE = \dfrac{50 \times 50 \: {kg}^{2} {m}^{2} {s}^{ - 2} }{30 \: kg}⟼KE=

30kg

50×50kg

2

m

2

s

−2

⠀

\longmapsto \sf \:KE = \dfrac{2500 \: {kg}^{2} {m}^{2} {s}^{ - 2} }{30 \: kg}⟼KE=

30kg

2500kg

2

m

2

s

−2

⠀

\longmapsto \sf \:KE = \dfrac{2500 \: kg {m}^{2} {s}^{ - 2} }{30}⟼KE=

30

2500kgm

2

s

−2

⠀

\longmapsto \sf \:KE = 83.33 \: kg {m}^{2} {s}^{ - 2}⟼KE=83.33kgm

2

s

−2

⠀

\longmapsto{\underline{\boxed{\purple{\sf{KE = 83.33 \: J}}}}}⟼

KE=83.33J

⠀

Hence,

the kinetic energy is 83.33 Joule.

Answer 2

Answer:

$\underline{\underline{ \sf \huge \red{Answer :-}}}$

kinetic energy :-

∴ v = p/m ==>>30Kg m/s