The momentum of a body of mass 5 kg is 10 kg metre per second a force of 2 newton acts on the body in the direction of motion of 5 seconds the increase in the kinetic energy is
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hii mate!!!
According to the Newton’s second law,
F = change in momentum/ time period
Initial kinetic energy = 1/2 × 5 × 4 = 10J
Let final momentum be p
So,
0.2= p-10/10
2= p-10
p=12
mv=12 => v=2.4
Final Kinetic energy= 1/2 mv^2
Or = 1/2 (mv) v =>1/2 pv
= 1/2 × 12 × 2.4
=14.4 J
Increase in kinetic energy = 14.4 - 10 = 4.4J
:)hope it helps !!☺☺☺☺
According to the Newton’s second law,
F = change in momentum/ time period
Initial kinetic energy = 1/2 × 5 × 4 = 10J
Let final momentum be p
So,
0.2= p-10/10
2= p-10
p=12
mv=12 => v=2.4
Final Kinetic energy= 1/2 mv^2
Or = 1/2 (mv) v =>1/2 pv
= 1/2 × 12 × 2.4
=14.4 J
Increase in kinetic energy = 14.4 - 10 = 4.4J
:)hope it helps !!☺☺☺☺
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