Physics, asked by jeshu7212, 1 year ago

The momentum of a bullet of mass 20 gm fired from a gun is 10 kg-m/s. the kinetic energy of bullet in kj wil be

Answers

Answered by faaiza623

8

p=mxv
10=0.02xv
500m/s=v
k=1/2mv2
=1/2x0.02x500x500
=2500J

Answered by jaysolanki2007

1

Answer:

p=mxv

10=0.02xv

500m/s=v

k=1/2mv2

=1/2x0.02x500x500

=2500J

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