The momentum of a bullet of mass 20g fired from a gun is 10kgm/s. Calculate the kinetic energy of this bullet in kJ.
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Now, we have kinetic energy
K. E. = 1/2 mv^2
= 1/2[ (mv) ^2]/m [ a = a^2/a]
= (mv)^2 / 2m
We know, momentum (p) = m*v
So, (10)^2 / 2*20
= 100/40
= 2.5
If helps, please mark it as brainliest ^_^
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