Question

The momentum of a particle which has a de-
Broglie wavelength of 0.1 nm is
(1) 3.2 x 10-24 kg ms-1 (2) 4.3 x 10-22 kg ms-1
(3) 5.3 x 10-22 kg ms-1 (4) 6.62 x 10-24 kg ms-1

Answer 1

Answer(4). 6.626.10^-24

Explanation:lamda=h(plank's constant)/p(momentum

0.1.10^-9=6.626.10^-34/p

1.10^-10=6.626.10^-34/p

p=6.626.10^-34/1.10^-10

p=6.626.10^-24