Question

The momentum of a particle which has a de Broglie wavelength of 0.1 nm

Answer 1

Answer:

6.626x10^-24kg m/s

Explanation:

Acc to de broglie expression

wavelength=h/p where

p is momentum and h is plancks constant(6.626 x 10^-34Js)

hence p=h/wavelength

p=6.626x10^-34Js/1x10^-10m

p=6.626x10^-24 kg m/s

Answer 2

Answer:

using the formula λ= h/mv we can find the answer

h is planck's constant = 6.6 * 10^-34

λ = 1 * 10^-10 (given)

Explanation: