Question

The momentum of a photon of energy 1 mev in kg m/s will be

Answer 1

momentum=mass×velocity
by using e=mc^2 and m=e/c^2,
momentum=energy/speed of light^2×velocity of light^2
so,
momentum=energy
momentum=1kg m/s

Answer 2

Given :

Energy of photon ,

$E = 1\ Mev=1\times 10^6\times 1.6\times 10^{-19}\ J\\\\E=1.6\times 10^{-13}\ J$ .

To Find :

The momentum of a photon in kg m/s .

Solution :

We know , momentum is given by :

$p=\dfrac{E}{c}$   ....( 1 )

Here , c is speed of light , $c=3\times 10^8\ m/s$ .

Putting all these in equation 1 .

We get :

$p=\dfrac{1.6\times 10^{-13}\ J}{3\times 10^8\ m/s}\\\\p=5.33\times 10^{-22}\ kg\ m/s$

Therefore , this is the required solution .

Learn More :

Momentum of photon

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