The momentum of a projectile makes an angle of 45 degree with the vertical. If air is assumed to be absent , then the change in momentum, along vertical from the point of projection to the point where the projectile returns to the plane of projectile is given by
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Answer: mv√2
Explanation:
Uy= v/√2j
Vy= -v/√2j
Change in momentum in vertical direction is: final - initial = -mv/√2-mv/2=-2mv/√2 = -mv√2
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