Question

The momentum of abidy is given by p=(10t²i+5tj^)kgm/s .Find the force acting on the body at t=2s

Answer 1

p is equal to f X t

Answer 2

The force acting on the body at t = 2 s is $(40i+5j)\ N$.

Explanation:

Given that,

The momentum of a body is given by :

$p=(10t^2i+5tj)\ kg-m/s$

We need to find the force acting on the body at t = 2 s. We know that the rate of change of momentum of an object is equal to the force acting on it. It is given by :

$F=\dfrac{dp}{dt}$

$F=\dfrac{d(10t^2i+5tj)}{dt}$

$F=(20ti+5j)\ N$

At t = 2 s

$F=(20(2)i+5j)\ N$

$F=(40i+5j)\ N$

So, the force acting on the body at t = 2 s is $(40i+5j)\ N$. Hence, this is the required solution.

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Second law of motion

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