Question

The momentum of particle which has de broglie wavelength of 0.1 nm is

Answer 1

Answer:

0.015 * 10^25 kgm/s is the momentum of the particle

Explanation:

as the momentum and de Broglie wavelength is related by

L = h / p , where p is the momentum and L is the wavelength

now

0.1 * 10 ^-9 = 6.626 * 10 ^-34 / p

p = 0.015 * 10^25 kgm/s

Answer 2

Answer:

6.6 × 10^-24

Explanation:

L=H/P

6.6 ×10^-34÷0.1× 10^-9

6.6×10^-24 kgms^-1