Question

the momentum of the particle having the wave length of 1A is​

Answer 1

Answer:

6.6 X 10^-24 kgm/s

Explanation:

By the De Broglie's wavelength formula:

λ=h/p; where h=planck's constant

                               p=momentum; λ (lamda)=wavelength.

therefore, solution:

given,

  λ=  1A=10^-10m.(converting A to m(metres)).

   h=6.626X10^-34J/s.

   momentum(p)=?

   

  λ=h/p

  10^-10= 6.626 X 10^-34/p.

we get p=6.626 X 10^-34/10^-10.

(on solving we get)

p=6.6X10^-24 kgm/s.

Hope it helps you:)