The momentum p(in kg m/s) of a particle is varying with time t (in s) as p=2+3t^2 . The force acting on the particle at t=3s will be???
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Answers
Answered by
55
F = dp/dt
dp/dt = 6t
then the t =3 sec
dp / dt = 6(3)
F = 18 N
dp/dt = 6t
then the t =3 sec
dp / dt = 6(3)
F = 18 N
Answered by
2
Answer:
Force, F = 18 N
Explanation:
Given:-
Momentum, p = 2 + 3t² (variable with time)
Force asked at time, t = 3 s
We know that;-
∵ F = dP / dt [where force equals the rate of change of momentum w.r.t time]
∴ F = d( 2 + 3t² ) / dt
F = 6t
Force, at time, t = 3s is ;
F = 6 × 3
F = 18 N
Hence, the force acting on the particle at t = 3 s will be 18 N.
Hope it helps! ;-))
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