Physics, asked by Ashley234, 1 year ago

The momentum p(in kg m/s) of a particle is varying with time t (in s) as p=2+3t^2 . The force acting on the particle at t=3s will be???


Plzzzzzzz solve this problem in details.......,...

Answers

Answered by AJAYMAHICH
55
F = dp/dt

dp/dt = 6t

then the t =3 sec

dp / dt = 6(3)

F = 18 N
Answered by TheUnsungWarrior
2

Answer:

Force, F = 18 N

Explanation:

Given:-

    Momentum, p = 2 + 3t² (variable with time)

    Force asked at time, t = 3 s

We know that;-      

∵            F = dP / dt  [where force equals the rate of change of momentum w.r.t time]

∴           F = d( 2 + 3t² ) / dt

               F = 6t

Force, at time, t = 3s  is ;

               F = 6 × 3

               F = 18 N

Hence, the force acting on the particle at t = 3 s will be 18 N.

Hope it helps! ;-))

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