Science, asked by Anuragenius, 3 months ago

the momtumom of a bullet of mass 20 gm is 16 kg m/s the kinetic energy of this bullet will be

Answers

Answered by gisksyash19
9

Answer:

The mass of bullet is 20 g or 0.02 kg.

The momentum of the bullet is 10 kg⋅m/s

The kinetic energy of a body in terms of its momentum is given as:

KE=

2m

KE=

2×0.02

10×10

2500 J= 2.5 kJ

Answered by kikibuji
30
  • Momentum of the bullet, p = 16 kgm/s

  • Mass of the bullet, m = 20 gram.

1 \: g \:  =  {10}^{ - 3}  \: kg \\  \\ 20\: g \:  = 20 \times  {10}^{ - 3}  \: kg \\    \\ m = 2 \times  {10}^{ - 2} kg

We know that,

Momentum, p = m× v

where v is the velocity of the bullet.

16 = 2 \times  {10}^{ - 2}  \times v \\  \\ v =  \dfrac{16}{2 \times  {10}^{ - 2} }  \\  \\ v =  \dfrac{16 \times  {10}^{2} }{2}  \\  \\ v = 8 \times  {10}^{2}  \:  \frac{m}{s}

Velocity of the bullet, v = 8 × 10² m/s.

Let k be the kinetic energy of the bullet.

Kinetic energy,

k =  \dfrac{1}{2} m {v}^{2}  \\  \\  =  \frac{1}{2}  \times 2 \times  {10}^{ - 2}  \times  {(8 \times  {10}^{2}) }^{2}  \\  \\  =  {10}^{ - 2}  \times 8 \times 8 \times  {10}^{4} \\  \\  = 64 \times  {10}^{ (- 2 + 4)}   \\  \\  k= 64 \times  {10}^{2}  \: joules \\  \\  = 64 \times 100 \\  \\  k= 6400 \: joules

Kinetic energy of the bullet is 64×10² J or 6400 J.

Similar questions