The monkey is climbing a vertical tree with a velocity of 5 m/s and a dog is running towards the tree with a velocity of with velocity of 5√3ms-1.the velocity of the dog relative to the monkey is: And with what Angle to horizontal?
Answers
Answer:
5m/s is the correct answer of this question
Answer:
The relative velocity of the dog with respect to the monkey is (5√3, -5) m/s, and the angle that it makes with the horizontal is -30 degrees.
Explanation:
The monkey is mountaineering a vertical tree with a pace of 5 m/s and a canine is going for walks closer to the tree with a pace of with pace of 5√3ms-1.
To calculate the relative speed of the canine with appreciate to the monkey, we want to subtract the speed of the monkey from the pace of the dog.
The pace can be represented as (0, 5) m/s.
The pace of the canine can be represented as (5√3, 0) m/s.
To discover the relative speed of the canine with appreciate to the monkey:
Relative speed = Velocity of canine - Velocity of monkey
= (5√3, 0) - (0, 5)
= (5√3, -5)
So the relative pace of the canine with admire to the monkey is (5√3, -5) m/s.
The perspective that the relative speed makes with the horizontal can be discovered the use of trigonometry. The tangent of the attitude is the vertical element of the relative speed divided with the aid of the horizontal component:
tan(θ) = -5 / 5√3
θ = arctan(-1/√3)
θ = -30 tiers (measured from the horizontal in the clockwise direction)
Hence,
The relative pace of the canine with admire to the monkey is (5√3, -5) m/s, and the perspective that it makes with the horizontal is -30 degrees.
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