Math, asked by ItzUrDeewani13, 3 days ago

the monthly income of a and b are in the ratio of 4:5 and their monthly expenses are in the ratio of 11:15, is each of them saves rs.2000 find the income of a​

Answers

Answered by Johnsonmijo
0

Answer:

If monthly income of a and b are in the ratio of 4:5 and their monthly expenses are in the ratio 11:15 and if each of them saves Rs 2000, then income of a is Rs 6400

Step-by-step explanation:

Given

Ratio of monthly income of a and b= 4:5

So if income of a is 4x, income of b is 5x

Given

Ratio of monthly expenses of a and b = 11:15

So if a spends 11y b spends 5y

Given that each of them saves Rs 2000

That amount a saves = monthly income of a - monthly expenses of a

2000 = 4x -11y

Amount b saves = monthly income of b- monthly expenses of b

2000= 5x-15y

2000= 5(x-3y)\\    \frac{2000}{5} = (x-3y)\\\\                       x-3y = 400\\                       x=400+3y

Sustitute for x in equation

2000 = 4x -11y

2000 = 4(400+3y) -11 y

2000= 1600+12y-11y

2000-1600=y

y=400

x= 400+3y

= 400+1200

=1600

Income of a = 4x

= 4*1600

= 6400

Therefore monthly income of a is Rs 6400

Answered by aditya541677
0

Answer:

Hey apka intro

Step-by-step explanation:

P1 = 449.249] 0.9. Calculate price index number for 2016 of following data by weighted aggregative method using: (a) Laspeyre's method, (b) Paasche's method, (c) Fisher's method. Commodity Quantity Price (2012) 4 Price (2016) (2012) 20 000 Quantity (2016) A 6 10 B 3 15 5 23 C 2 25 3 15 D 5 10 4 40 [Laspeyre's: 137.77, Paasche's: 158.99, fisher's = 148.1]

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