Question

The monthly salary of 10 employees in a factory are given below:$5000,$7000,$8000,$7000,$7000,$5000 Find the mean,median and mode​

Answer 1

$\huge\mathcal\colorbox{red}{{\color{blue}{Solution}}}$

⟹The monthly salary of 10 employees are Rs 5000, Rs 7000, Rs 5000, Rs 7000, Rs 8000, Rs 7000, Rs 7000, Rs 8000, Rs 7000, Rs 5000.

⟹ Writing in ascending order Rs 5000, Rs 5000, Rs 5000, Rs 7000, Rs 7000, Rs 7000, Rs 8000, Rs 8000

⟹Number of values = 10 which is an even number.

⟹ Median the-monthly-salary-employees-factory-are-given-below-5000-rs-7000-5000-7000-8000-7000-17000

⟹Average of

$= > \frac{10^{th} }{2} and \: ( \frac{(10 + 1)^{th} }{2} ) \: value$

⟹Average of

$5 ^{th} and \: {6}^{th} \: value$

$= > \frac{7000 + 700}{2} = \frac{14000}{2} = rs. \: 7000 \\ means \: \binom{ - }{x} \\ \\ \frac{x}{n} = \frac{5000^{2} + 7000 {}^{4} +8000 {}^{2} }{10} \\ = > \frac{66000}{10} = rs.6600$