the monthly salary of a teacher is ₹12, 800.if his annual increment is 3 ०/०, find his new salary after an year.
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0
Answer:
3/100X12800
=3X128
=384
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1
Monthly salary = ₹ 12,800
Annual increment = 3%
Therefore, monthly salary after an year = (100+3)% of 12,800
= 103% of 12,800
= 103/100 x 12,800
= 13,184
Therefore, monthly salary after an year= ₹ 13,184.
Please mark as brainliest.
Annual increment = 3%
Therefore, monthly salary after an year = (100+3)% of 12,800
= 103% of 12,800
= 103/100 x 12,800
= 13,184
Therefore, monthly salary after an year= ₹ 13,184.
Please mark as brainliest.
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