Question

The moon completes one revolution around the earth
in 27 days in an orbit of radius 3.8 x 10power5 km. The
earth completes one revolution around the sun in 365
days in an orbit of radius 1.5 x 10power8 km. Compare the
masses of the sun and the earth.​

Answer 1

Answer:

Explanation:

kepler's third law state that

∴$\frac{t^{2} }{r^{3} } = \frac{4\pi ^{2}}{GM}$

ACCORDINGLY,

MASS OF EARTH = $\frac{4\pi ^{2} *r^{3}  }{t^{2} G}$

           =$\frac{4\pi ^{2} }{G}$ * (3.8 *10^5*1000 )³/(27*24*60*60)²

MASS OF SUN=$\frac{4\pi ^{2} }{G}$*(1.5*10^8*1000)³/(365days)²

           =$\frac{4\pi ^{2} }{G}$*(1.5*10^8*1000)³/(365*24*60*60)²

mass of sun /mass of earth = 4.5 *10^5 (approx)