Physics, asked by Safwaan30, 1 year ago

The moon is revolving around the earth in a circular path. How much work is done by the moon.?

Answers

Answered by MrJ109

$work \: done \: by \: the \: moon \: is \: 0. \: this \: is \: because \: the \: work \\ \: done \: = force \: \times displacement \cos(theta) \\ now \: when \: moon \: is \: attracted \: by \: earth \: s \: gravitational \: force \\ it \: should \: have \: gone \: in \: the \: direction \: of \: earth \: that \\ is \: towards \: earth \: but \: its \: displacement \: is \: \\ perpendicular \: to \: the \: direction \: of \: force \\ that \: is \: tangential. \: so \: theta = 90 \\ and \: \cos(90) = 0 \\ w = fs \cos(90) \\ w = 0 \: \\ here \: w = work \\ f = force \\ s = displacement$

MrJ109: if you like my answer do mark it as brainliest. .....and if you don't understand anything. . . please ask me.....

Safwaan30: MrJ109, your answer is very brainly but complicated. actually, i am a class 8 student and haven't started logarithms.. si

Safwaan30: so.. its little hard forme... anyway thanks a lot for giving your very valuable time

MrJ109: don't worry friend if you are in class 8 your teacher must have taught you that work =0 when displacement is perpendicular to force acting.....you can just remember it for the time being.......you will come to know it's reason when you will come in your higher classes

Safwaan30: ok.. thank u so much

MrJ109: thanks friend

Safwaan30: you are welcome

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