The Moon orbits the Earth once in 27.3 days in almost circular orbit. Calculate the centripetal acceleration experienced by the Earth. (Radius of the Earth is 6.4×10^6m)
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Answered by
4
Answer:
The centripetal acceleration is given by a=
6
v
2
This expression explicity depends on Moon's speed which i s non trivial . we can work with the formula w
2
R
m
=a
m
Since,
a
m
→ centrifugal acceleration of the moon due to earth's gravity
w→ angular velocity
R
m
=60R=60×6.4×10
6
=384×10
6
m is the distance between earth and the moon, which is 60 times the radius of the earth.
w=
T
2π
angular velocity w=
T
2π
.
and T=27.3days=27.3×24×60×60
Seconds=2.358×10
6
sec
putting these values in the formula for acceleration
a
m
=
(2.358×10
6
)
2
(4π
2
)(384×10
6
)
=0.00272ms
−2
Explanation:
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Answered by
0
Explanation:
moons centripetal acceleration is 2.7×10^-3m/s^2
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