The moon radius is 1/4 that of the of the earth and massis 1/80 that of the earth .If g representns accleration due to gravity on the surface of the earth than on surface of the moon
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g= GM/R^2
g' = G (M/80) / (R/4)^2
g' = GM/(5R^2)
g' = (1/5)*(GM/R^2)
g' = g/5
so gravity will be (1/5) times.
g' = G (M/80) / (R/4)^2
g' = GM/(5R^2)
g' = (1/5)*(GM/R^2)
g' = g/5
so gravity will be (1/5) times.
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