Physics, asked by swaradagokhale2005, 1 month ago

The most accurate reading of mass 25.0 g is 0 24.00 g 0 24.800 g 0 25.1 g 0 25.20 g

Answers

Answered by amitnrw
2

Given : reading of mass 25.0  g is    24.00 g  ,  24.800 g ,  25.1 g ,  25.20 g

To Find : most accurate reading

Solution:

most accurate reading is the reading which is closet to actual value

Actual value = 25.00  g

24.00 g    has a difference from  25.00    =   | 24.00 - 25.00|  = 1 g

24.800    has a difference from  25.00    =   |24.800 - 25.00|  = 0.200 g

 25.1    has a difference from  25.00    =   |  25.1  - 25.00|  = 0.1 g

25.20 g    has a difference from  25.00    =   | 25.00 - 25.00|  = 0.2 g

0.1 g is the least value

Hence 25.1 g  is most accurate reading of mass 25.0 g

Learn More:

the most precise and accurate measurements are

brainly.in/question/35920267

The true value of a certain length is 4.468m

https://brainly.in/question/35911644

Answered by rohitkumargupta
3

HELLO DEAR,

GIVEN:-

\large{The\: most\:accurate\:}\\\large {\:reading \:of \:mass\: 25.0\: g\: is\:} \\\large{A)\:24.00 g} \\\large{B)\:24.800 g}\\\large {C)\:25.1 g }\\\large{D)\:25.20 g}

\large\red{   Accuracy-}\large{\: It \:is\: closeness\: of\: the\:}\\\large{measurements\: to\: a \:specific \:value.\:}

\large\red{   Precision-}\large{ \:It\: is\: closeness\: of\:}\\\large{ \:the\:measurements\: to \:each\:}\\\large{ \:other.\:}

\large{  To\: find\: the\: more\:}\\\large{ accurate\:reading\: from\:}\\\large{ the\: given\: options.\:}

\large{ The\: difference \:between \:}\\\large{\:accurate\: reading\: to\: given \:}\\\large{reading\: is \:less\: Know \:as\:}\\\large{more \:accurate\: reading.\:}

\large{The \:accurate \:mass\: of\:}\\\large{\: the \:object\: = 25.0 g\:A) \:24.00 g\:}\\\large {=>\: 25.0\: - \:24.0\: = \:1.0 g\:}\\\large{  B)\: 24.80 \:g}\\\large {=> \:25.00\: - \:24.80\: = \:0.2 g\:}\\\large { C) \:25.10 g }\\\large{=>\: 25.10\: -\:25.00\: = 0.1 g}\\\large {  D) \:25.20 g}\\\large { =>\: 25.20\: - 25.00\: = \:0.2 g.}\\\large{ The \:most \:less \:value \:obtained \:}\\\large{\:from \:the \:difference \:of\:}\\\large{given\: option\: is\: 0.1 g}\\\large{\:of \:option \:C) \:25.10 g .}\\\large  {Therefore, \:option \:(C) \:25.10 \:g}\\\large{ \:is\: right\: option.\:}

THANKS.

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