Chemistry, asked by AnshumanPani5944, 1 year ago

The most predominantly ionic compounds will be obtained from the combination of elements belonging to
A) 1 and 7 groups B) 2 and 6 groups C) 3 and 5 groups D) 0 and 7 groups

Answers

Answered by aman6810
18
a 1 and 7 ....................
Answered by RomeliaThurston
10

Answer: The correct answer is Option A.

Explanation:

Ionic compound is formed whenever there is complete transfer of electrons from 1 atom to another atom forming a bond. The atom which looses electron is called as electropositive atom and atom which gains an electron is termed as electronegative atom.

For the given options:

Option 1: 1 and 7 groups

Electronic configuration of Group 1: ns^1

Electronic configuration of Group 7: ns^2np^5

Group 1 will easily loose 1 electron which will be accepted by Group 17. Hence, this will readily form ionic compound.

Option 2: 2 and 6 groups

Electronic configuration of Group 2: ns^2

Electronic configuration of Group 6: ns^2np^4

Group 2 will loose 2 electron and require more energy which will be accepted by Group 6. Hence, these groups will not readily form ionic compound.

Option 3: 3 and 5 groups:

Electronic configuration of Group 3: ns^2np^1

Electronic configuration of Group 5: ns^2np^3

Group 3 will loose 3 electrons and require more energy which will be accepted by Group 5. Hence, these groups will not readily form ionic compound.

Option 4: 0 and 7 groups

Electronic configuration of Group 0: ns^2np^6

Electronic configuration of Group 7: ns^2np^5

Group 0 will not loose or gain electrons and hence, will not form any compounds.

From the above information, the correct answer is option A.

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