Question

- The mother's age is 4 times her daughter's age.
Four year hence, the age of mother will be one
year more than three times her daughter's age. The
present ages in years of daughter and mother are,
respectively
(1) 8 and 32
(2) 13 and 52
(3) 12 and 48
(4) 9 and 36​

Answer 1

Answer:

A woman (w) is (=) currently three times (3*) as old as her daughter (d). Four years ago (w-4) she was (=) four times (4*) as old as her daughter was then (d-4). What are their current ages (what are w and d)?

So we’ve got our two equations from the problem:

w = 3*d

w - 4 = 4*(d-4)

Now we rearrange a bit so they both just have w on one side

w = 4*d - 12

Replace that w with the right side of the first equation

3*d = 4*d - 12

Solve for d

d = 12

And plug that into either original equation to get w

w = 36

Step-by-step explanation:

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