The motion of a ball dropped from a height of 20 m is a uniformly accelerated motion discuss
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Explanation:
Given, initial velocity of ball, u=0
Final velocity of ball, v=?
Distance through which the balls falls, s=20m
Acceleration a=10ms−2
Time of fall, t=?
We know
v2−u2=2as
or v2−0=2×10×20=400 or v=20ms−1
Now using v=u+at we have
20=0+10×t or t=2s
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