the motion of a body of mass 5kg is shown in v-t graph.find from graph its acceleration,the force on the body and the change in the momentum of the body 2 seconds after start.
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It is difficult to see calculate the slope without the millimeter grid on the graph. Assume that units for velocity are m/s.
Draw vertical lines at t=2, 4 and 6 sec. From the points of intersections, draw horizontal lines onto y axis.
Still using a scale I find that at t=2s, v=4.5m/s...
At t=6s, v=13.5s... At t=0s, v=0.
Slope of v-t graph = a = acceleration.
a = (13.5-0)/(6-0)= 2.25 m/s.
Force = m a = 5*2.25= 11.25 N
Change in momentum in 2 sec. = m(v2- v1)
= 5 (4.5 - 0) = 22.5 kg-m/s
Draw vertical lines at t=2, 4 and 6 sec. From the points of intersections, draw horizontal lines onto y axis.
Still using a scale I find that at t=2s, v=4.5m/s...
At t=6s, v=13.5s... At t=0s, v=0.
Slope of v-t graph = a = acceleration.
a = (13.5-0)/(6-0)= 2.25 m/s.
Force = m a = 5*2.25= 11.25 N
Change in momentum in 2 sec. = m(v2- v1)
= 5 (4.5 - 0) = 22.5 kg-m/s
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