Physics, asked by nehadeepak2002, 1 month ago

The motion of a car along y-axis is given by the relation y = t^3 - 6t^2 +9t + 5, where y is in metre and t is in second. Calculate the position, acceleration and total distance travelled at t = 5 second.

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Answered by akshay1921

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The motion of a car along y-axis is given by the relation y = t^3 - 6t^2 +9t + 5, where y is in metre and t is in second. Calculate the position, acceleration and total distance travelled at t = 5 second

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The motion of a car along y-axis is given by the relation y = t^3 - 6t^2 +9t + 5, where y is in metre and t is in second. Calculate the position, acceleration and total distance travelled at t = 5 second.​

Answers

The motion of a car along y-axis is given by the relation y = t^3 - 6t^2 +9t + 5, where y is in metre and t is in second. Calculate the position, acceleration and total distance travelled at t = 5 second.