the motion of a car along y-axis is given by the relation y=t^3-6t^2+9t+5 where y is in metre and t is in second calculate the position,acceleration and total distance travelled at t=5 seconds
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3t^2-12t+9+0=dy/dt
so at t=5
dy/dt=24m
so at t=5
dy/dt=24m
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