The motion of a car along y-axis is given by v (t) = -12t + 12 where velocity v is in m/s and time t in seconds. Find the instantaneous position of the car as a function of time if at t = 0 it was at 5m. Also find its acceleration at t = 2 second.
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Answer:
From the table, we will find out velocity at each interval;-
t 0 1 2 3
x(m) -2 0 6 16
v=
△t
△x
- 2 6 10
[
△x=x
i
^
−x
i
^
−1
△t=t
i
^
−t
i
^
−1=1
]
Clearly, v now varies with t linearly as v=4t−2
This.
dt
dv
=4, which is constant >0
⇒ It is a unifformly accelerated motion.
Explanation:
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