Question

the motion of a particle along a straight line is described by the function s = 6 + 4t^2 - t^4 in SI units find the velocity and acceleration at t= 2 seconds find average velocity during 3rd second.​

Answer 1

Answer:

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Given distance time relationship.

s = 6 + 4t^2 + t^4

Distance traveled in 2 s

s2s2 = 6 + 4*2^2 + 2^4

s2s2 = 6 + 16 + 16 = 38 m

Similarly distance traveled in 3 s

s3s3 = 6 + 4*3^2 + 3^4

s3s3 = 6 + 36 + 81 = 123 m

Distance traveled during 3rd second

s3−s2s3−s2 = 123 - 38 = 85 m

Average velocity during 3rd second = 85/1 = 85 m/s.

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