Question

the motion of a particle along x-axis is given by the equation X = 9 + 5t^2 where x is distance in centimetres anti is time in second . average velocity during the interval from T = 3 second to t = 5 second is​

Answer 1

Explanation:

just differentiate and integrating them u get urs answer perfectly

Answer 2

Answer:

(1)

Position at t=3 s, x1=9+5(3)2=54 cm    

Position at t=5 s , x2=9+5(5)2=134 cm

The average velocity of an object is the ratio of change is position to time interval in which displacement occurs,i.e

v⃗ =displacementtime interval=∆x⃗ ∆t   =x2−x1t2−t1=134 cm−54 cm5s−3s=802=40 cm/s

(2)  Instantaneous velocity, vi=dxdt=d(9+5t2)dt=10t

                                       at t=3s , vi=10(3)=30cm/s

Explanation:

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