The motion of a particle is defined by the relation x = 2t4 – 6t3 + 3t + 3, where x and t are
expressed in meters and seconds, respectively. Determine the time, the position, and the
velocity when a = 0.
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Answer:
Explanation:
x=2t⁴-6t³+3t+3
v=dx/dt=d(2t⁴-6t³+3t+3)/dt=8t³-18t²+3
a=dv/dt=d(8t³-18t²+3)/dt=24t²-36t+3
given that acceleration is 0
therefore,
24t²-36t+3=0-----find the roots of this quadratic equation.
the positive time will be the answer
put that time in the equation of 'x' and get the position
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