Question

the motion of a particle is described by the equation u=at . The distance travelled by the particle in the first 4 secs ?

Answer 1

if u=at

Then s = $\frac{1}{2}at^{2}$

When t=4 s

s = 8a

Answer 2

Answer:

The distance traveled by the particle in the first 4 secs is 8a.

Explanation:

From the question we have,

$u=at$      (1)

Where,

u=velocity with which the particle is moving

a=acceleration of the particle

t=time during which the motion occurs

Also,

$ds=udt$     (2)

s=distance traveled by the particle

By placing equation (1) in equation (2) we get;

$ds=atdt$

$ds=\frac{at^2}{2}$     (3)

We get the following results by substituting "t=4 sec" into equation (3):

$ds=\frac{a(4)^2}{2}$

$ds=\frac{a\times 16}{2}$

$ds=8a$

Hence, the distance traveled by the particle in the first 4 secs is 8a.

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