Question

The motion of a particle is given by y = 40t-st² and x= 40√3 t when x and Y are in metres and 't' in Seconds. Then initial Velocity of the body and angle made by it to the horizontal are​

Answer 1

Answer:

x=6t

on differentiating with respect to t

v

x

=6

y=8t−5t

2

v

y

=8−5t

at t=0 v

y

=8

v

2

=6

2

+8

2

=10

2

v=10m/s

Explanation:

please Mark as Brainlist answer