The motion of a particle of mass 50 gm is given by x. 10t +100t^2 . fin d the force acting on the particle.
Answers
Answer:
Mass of the particle, m = 50 gm
The equation of motion of particle is,
x = 10t + 100t2
Therefore acceleration of the particle is,
straight a equals fraction numerator straight d squared straight x over denominator dt squared end fraction equals 200 straight m divided by straight s squared
The force acting on the particle is,
F = ma = 0.05 x 200 = 10 N
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