Question

the motion of a particle of mass and is given by

y=ut+1/2gt^2
find a force acting on the particle

it is for 2 marks ​

Answer 1

since y is displacement and function of time t, differentiating it with respect to t gives velocity and differentiating velocity with respect to t gives acceleration

$y = ut + 1 \div 2 \: gt ^{2} \\ d \div dt(y) = 1 + gt \\ d ^{2} y \div dt ^{2} = g$

so if mass is m and accln is g

force acting at any instant= mass × accln

=m×g (Ans)

Answer 2

Hope it helps..................