Question

The motion of a partide along a straight line to
described
by the equation x=8+12t-t^3,where x is meter and t in sec ​

Answer 1

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Answer 2

x = 8+12t−t^3

v = dx / dt

v = 12 − 3t^2

∴V=0 at t = ± 2s, negative time has no significance,

∴t=2s

a = dv / dt = −6t

∴a at t = 2 = −6 × 2 = −12m/s^2

Thus, retardation when velocity becomes 0 is 12ms^−2

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