Question

the motional EMF induced in a rod moving perpendicular to the magnetic field is given by​

Answer 1

Answer:

e=blv

Explanation:

consider a rectangular conducting loop PQRS. let B be the magnetic field acting on the and A be the area of cross section.

let the length of the rectangular loop be l and breadth be x

let RS be the rod moving with velocity v

now,

the total magnetic flux linked with rectangular loop is given by -

phi =BA

phi=Blx (since A=l×x)

here as RS is moving , x changes with time.

therefore, the rate of change of flux can be found by Faraday second law -

|e| = d/dt(phi) =d/dt(Blx) = Bl.d/dt(x)

therfore |e| = blv