Question

The moving coil galvanometer made 200 turns of thin wire is suspended from elastic thread the area of coil is 1 cm^2 magnetic field is 15 mt

Answer 1

Answer:

Answer is given in picture

Answer 2

The torsional constant of the suspension wire is $6\times10^{-5}\ N m/rad$

Explanation:

Given that,

Number of turns = 200

Area = 1 cm²

Magnetic field = 15 mT

Suppose, The deflection in the coil is 0.05 radian when a current of 10mA is passed through it. Find the torsional constant of the suspension wire.

We need to calculate the torsional constant of the suspension wire

Using formula of current

$I=\dfrac{k}{nAB}\theta$

$k=\dfrac{nABI}{\theta}$

Where, I = current

A = area

B = magnetic field

Put the value into the formula

$k=\dfrac{200\times1\times10^{-4}\times15\times10^{-3}\times10\times10^{-3}}{0.05}$

$k=6\times10^{-5}\ N m/rad$

Hence, The torsional constant of the suspension wire is $6\times10^{-5}\ N m/rad$

Learn more :

Topic : magnetic field

https://brainly.in/question/2828344