the mth term AP is n and nth term is m.The r th term of it is
A. M+n+r
B. N+m-2r
C. M+n+r/2
D. None of these
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Answer - Option (D) - None of these
Let a be the first term and d be the common difference.
Given that mth term of an AP is n.
Tm = a + (n - 1) * d
n = a + (m - 1) * d -------------- (1)
Given that nth term of an AP is m.
Tn = a + (n - 1) * d
m = a + (n - 1) * d ------------------- (2)
Now,
On solving (1) & (2), we get
a + (m - 1) * d - a + (n - 1) * d = n - m
a + md - d - a - nd + d = n - m
md - nd = n - m
d(m - n) = n - m
d = n - m/m - n
d = -(m - n)/m - n
d = -1.
Substitute d = -1 in (2), we get
m = a + (n - 1) * (-1)
m = a - n + 1
a = m + n - 1.
Now,
Rth term tr = a + (r - 1) * d
= m + n - 1 + (r - 1) * (-1)
= m + n - 1 - r + 1
= m + n - r.
Therefore the rth term = m + n - r.
Hope this helps!
Let a be the first term and d be the common difference.
Given that mth term of an AP is n.
Tm = a + (n - 1) * d
n = a + (m - 1) * d -------------- (1)
Given that nth term of an AP is m.
Tn = a + (n - 1) * d
m = a + (n - 1) * d ------------------- (2)
Now,
On solving (1) & (2), we get
a + (m - 1) * d - a + (n - 1) * d = n - m
a + md - d - a - nd + d = n - m
md - nd = n - m
d(m - n) = n - m
d = n - m/m - n
d = -(m - n)/m - n
d = -1.
Substitute d = -1 in (2), we get
m = a + (n - 1) * (-1)
m = a - n + 1
a = m + n - 1.
Now,
Rth term tr = a + (r - 1) * d
= m + n - 1 + (r - 1) * (-1)
= m + n - 1 - r + 1
= m + n - r.
Therefore the rth term = m + n - r.
Hope this helps!
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