Math, asked by shivmsingh9648, 1 month ago

The multiple of 13 which on dividing by 4 5 6 7 and 8 leaves remainder 2 in each

Answers

Answered by bondmujeeb6
0

Answer:

LCM of 4, 5, 6, 7 and 8 = 840. Let require number be 840 K + 2 which is multiple of 13. 3 + 2 = 2520 + 2 = 2522.

Step-by-step explanation:

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Answered by cvayush
1

Step-by-step explanation:

LCM of 4, 5, 6, 7 and 8 = 840. Let require number be 840 K + 2 which is multiple of 13. 3 + 2 = 2520 + 2 = 2522.

Hope it's helpful for you!

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