Question

The multiplication of two complex numbers (-1 + 2i) and (-3i + 2) is

Answer 1

Step-by-step explanation:

=(-1+2i)(-3i+2)

= (-1*-3i-1*2-2i*3i+2*2i)

=(3i-2-6(i)^2+4i)

=(3i-2-6(-1)+4i)

=(7i-2+6)

=(7i+4)

Answer 2

Answer:

The multiplication of two complex numbers (-1 + 2i) and (-3i + 2) is (4 + 7i)

Step-by-step explanation:

Given two complex numbers are (-1+2i) and (-3i+2)

We want to multiply them.

So,

$( - 1 + 2i) \times ( - 3i + 2) \\ = + 3i - 2 - 6 {i}^{2} + 4i \\ = 3i - 2 + 6 + 4i \\ = 4 + 7i$

Here applied formula,

${i}^{2} = - 1$

This is a problem of complex numbers of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

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